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  1. How do you calculate the modulo of a high-raised number?

    I need some help with this problem: $$439^{233} \\mod 713$$ I can't calculate $439^{223}$ since it's a very big number, there must be a way to do this. Thanks.

  2. Modular multiplicative inverse function in Python - Stack Overflow

    Does some standard Python module contain a function to compute modular multiplicative inverse of a number, i.e. a number y = invmod(x, p) such that x*y == 1 (mod p)? Google doesn't seem to give any...

  3. How to calculate a Modulo? - Mathematics Stack Exchange

    May 16, 2015 · Can someone show me a general step-by-step procedure on how I would be able to find out the 5 modulo 10, or 10 modulo 5. Also, what does this mean: 1/17 = 113 modulo 120 ? Because …

  4. How to calculate a Mod b in Casio fx-991ES calculator

    Dec 7, 2011 · I have been scouring the internet for a straightforward explanation of how to use a^b/c to calculate remainders of integer division on my Casio fx-9750GA PLUS and this was incredibly …

  5. How can I find a mod with negative number? [duplicate]

    $$11 \mod 7 = 4$$ For this I did a simple division and took its remainder: i.e. $$11 = 7 \cdot 1 + 4$$ Where $11$ was dividend, $7$ divisor, $1$ quotient and $4$ was remainder. But I have a problem …

  6. c++ - Calculating pow (a,b) mod n - Stack Overflow

    m' = c^d mod n = 13^7 mod 33 = 7. Note that we don't have to calculate the full value of 13 to the power 7 here. We can make use of the fact that a = bc mod n = (b mod n). (c mod n) mod n so we can …

  7. Modular exponentiation by hand ($a^b\\bmod c$)

    @ user26486 @ SimplyBeautifulArt : speaking of the Carmichael function, I actually use it extensively in my primality testing module - e.g. asserting n^360 mod composite-of-13-small-primes == 1, even …

  8. php - LuhnCalc and bpay MOD10 version 5 - Stack Overflow

    Here is a function I created using vb.net to calculate a mod 10 version 5 check digit

  9. number theory - Modular exponentiation using Euler’s theorem ...

    As suggested in the comment above, you can use the Chinese Remainder Theorem, by using Euler's theorem / Fermat's theorem on each of the primes separately. You know that $27^ {10} \equiv 1 …

  10. What, actually, is the modulo of a negative number?

    I read somewhere that you can calculate the proper modulo of negative numbers by hand some laymen's method of just adding numbers together. This would be helpful, because the a/b *b + a%b …